To get 400V DC output, you need 280V RMS. I suggest the following setup: 230V input -> big ass series resistor -> single phase variac -> 230 : 280V isolating transformer -> diode rectifier. The variac isn't strictly necessary, but it will help you control the final charge voltage of the capacitor bank to achieve consistent results. That is 1 microfarad is 1/1,000,000 farads. Hence 0.22 microfarad is 0.22 x 1/1,000,000 farads. Therefore the rectance of the capacitor appears as 14475.97 Ohms or 14.4 K Ohms.To get current I divide mains Volt by the rectance in kilo ohm.That is 230 / 14.4 = 15.9 mA. Effective impedance (Z) of the capacitor is determined by taking the load For Single phase 230v any of your phase i.e. Gray Black Brown and neutral = Single phase 230v However to derive Single phase 400v = connecting gray and black without the neutral to the Load This is still single phase because one of the cable is acting as neutral i.e. a return path back to the substation I hope this helps. Now, if you look at the “1,000 ÷ 1.732V” portion of this equation, you can see that by inserting the respective 3-phase voltage for “V” and multiplying it by 1.732, you can then divide that resulting quantity into “1,000” to get a specific number (or constant) you can use to multiply “kW” to get the current draw of that 3-phase An option how to make 230 VAC delta motor out of 400 VAC star 3-phase asynchronous motor. AC current is calculated by the power factor of 0.86 for single-phase supply and 0.8 for three-phase supply. Look at the table the 1 hp motor takes will be 1.3 A at 440 Volts three-phase at the same time while using single-phase it takes only 3.8 Amps. Also 5 HP three-phase motor takes 6.4 Amps. YGbLR1m. The equipment is wired for 250 amp 400 volt service. I need to know how many amps it would pull after using a transformer to step it down to 220v 3 Phase. If I use the general equation Watts = Volts X Amps I get 100,000 watts. If I plug that number into the equation using 220v I get 454.5 amps (100,000/220 = amps), which seems like far too much. Transformer Rating = 50 kVA = V 1 × I 1 = V 2 × I 2. Primary full-load current, I 1 = (50 × 1000 / 4000) = 12.5 A. Secondary full-load current, I 2 = (50 × 1000 / 400) = 125 A. b) Turns Ratio = N 1 / N 2 = V 1 / V 2 = (4000 / 400) = 10. You may also be interested in our Voltage Divider Calculator or Motor FLA Calculator. Rating: 4.8 /5 (512 First we must convert from hp to kW using this formula : 1 Hp = 0.746 kW. After that use the formula kW to ampere : For 3 phase power supply ; kW = I x V x 1.732 x pf. For 1 phase power supply ; kW = I x V x pf. Example :-. 1 unit induction motor power rated 25 hp,200 VAC,3 phase,90 % power factor,calculated the full load ampere. Calculation :-. Its a hydraulically operated machine, with a motor that runs from 3 phase/400v mains voltage. The machine is very simple, there is a hydraulic "directional valve" that has both an "up" solenoid and "down" solenoid to move the ram up or down when power is applied to the appropriate solenoid. The solenoids are marked 24V DC. Voltage in Single Phase Supply System: Single Phase Voltage = 230V (Phase to Neutral) Phase Voltage (VPH) = Line Voltage ÷ √3 = 400V ÷ √3 ≈ 230V Note: The Voltage between Phase and Neutral is known as Phase Voltage (VPH). Voltage in a Three Phase Supply System: Three Phase Voltage = 400V (Line to Line or Phase to Phase) No, the 400V wired motor will not run properly on 220 VAC from a VFD, although you could possibly adjust the output to half speed which would supply 25 or 30 Hz. You could get the same torque for the pump, but I don't know if it will pump water under those conditions.

how to get 400v from 230v